Depends how you use it (&a[3], sizeof(a[3])). But its type is still char. | Hacker News

Hacker Newsnew | past | comments | ask | show | jobs | submit

		edflsafoiewq on Sept 5, 2020 \| parent \| context \| favorite \| on: Massacring C Pointers (2018) Depends how you use it (&a[3], sizeof(a[3])). But its type is still char.

richardwhiuk on Sept 14, 2020 [–]

IIRC, both of those are undefined.

edflsafoiewq on Sept 21, 2020 | [–]

&a[3] is allowed, it's a one-past-the-end-of-the-array pointer. &a[4] would be UB (if it were evaluated).

sizeof(a[3]) is not evaluating a[3], so it also isn't UB.

Guidelines | FAQ | Lists | API | Security | Legal | Apply to YC | Contact